Project Euler – Problem 17

Problem 17:
If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.

If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?

NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 (one hundred and fifteen) contains 20 letters. The use of “and” when writing out numbers is in compliance with British usage.

import java.util.Vector;


class runner
{
	@SuppressWarnings("serial")
	static Vector map = new Vector(){{
		add(new Integer[]{1, 3}); add(new Integer[]{2, 3}); add(new Integer[]{3, 5}); add(new Integer[]{4, 4}); add(new Integer[]{5, 4}); add(new Integer[]{6, 3}); add(new Integer[]{7, 5}); add(new Integer[]{8, 5});	add(new Integer[]{9, 4});
		add(new Integer[]{10, 3}); add(new Integer[]{11, 6}); add(new Integer[]{12, 6}); add(new Integer[]{13, 8}); add(new Integer[]{14, 8}); add(new Integer[]{15, 7}); add(new Integer[]{16, 7}); add(new Integer[]{17, 9}); add(new Integer[]{18, 8}); add(new Integer[]{19, 8});
		add(new Integer[]{20, 6}); add(new Integer[]{30, 6}); add(new Integer[]{40, 5}); add(new Integer[]{50, 5}); add(new Integer[]{60, 5}); add(new Integer[]{70, 7}); add(new Integer[]{80, 6}); add(new Integer[]{90, 6});
		add(new Integer[]{100, 7}); add(new Integer[]{1000, 8});
	}
	};



	public static void main (String[] args) throws java.lang.Exception
	{
		long time = System.currentTimeMillis();

		int sum = 0; int n = 1000;
		for(int i = 1; i<= n; i++){
			boolean BRITISH_AND = false;
			int cur = i;
			int length = 0;

			for(int j = map.size()-1; j>-1; j--){
				if(cur == 0) break;

				Integer[] mapcur = map.elementAt(j);

				int counter = 0;
				if(mapcur[0] >= 100){//1000, 100
					while(cur > 0 && mapcur[0] <= cur){
						counter++;
						cur -= mapcur[0];
					}
					if(counter > 0){
						length += mapcur[1];//Add the base number 1000, 100

						//Add the counter value
						for(int z = 0; z100
						if(cur > 0){
							BRITISH_AND = true;
						}

					}
				}else{//Normal Number
					if(mapcur[0] <= cur){
						length += mapcur[1];
						cur -= mapcur[0];
					}
				}
			}
			if(BRITISH_AND) length += 3;

			sum += length;
		}

		System.out.println(sum);
		System.out.println("time: "+(System.currentTimeMillis() - time));
	}
}